If alpha+ beta = gamma,then cos^2beta+cos^2 alpha-2cos alpha.cos beta.cos gamma=
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Solution :
We have to prove,
cos2α+cos2β+cos2γ=1+2cosαcosβcosγ
We can write it as
cos2α+cos2β+cos2γ−1=2cosαcosβcosγ
L.H.S.=cos2α+cos2β+cos2γ−1
=cos2α+cos2β−1(1−cos2γ)
=cos2α+cos2β−sin2γ
=cos2α+cos2β−sin2(α+β) (As γ=α+β)
=cos2α+cos2β−(sinαcosβ+cosαsinβ)2
=cos2α+cos2β−sin2αcos2β−cos2αsin2β−2sinαcosβsinβcosα
=cos2α(1−sin2β)+cos2β(1−sin2α)−2sinαcosβsinβcosα
=cos2αcos2β+cos2βcos2α−2sinαcosβsinβcosα
=2cos2αcos2β−2sinαcosβsinβcosα
=2cosαcosβ(cosαcosβ−sinαsinβ)
=2cosαcosβcos(α+β)
=2cosαcosβcosγ=R.H.S
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