if alpha + beta is equal to 8 and Alpha square plus beta square is equal to 34 find the quadratic equation whose roots are alpha and beta
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alpha + beta=8
(alpha+beta)^2=34
Alpha square plus beta square is equal to alpha + beta whole square minus 2 alpha beta
therefore, 34=(8)^2- 2×alpha×beta
therefore, 34 = 64 - 2× alpha× beta
therefore, 2×alpha×beta= 64-34
therefore, 2×Alpha×Beta=30
therfore, alpha×beta=30/2 = 15
The required quadratic equation is x^2 - (alpha + beta)x + alpha×beta=0 answer is x^2 - 8 x + 15=0
^ this means raise to the power
(alpha+beta)^2=34
Alpha square plus beta square is equal to alpha + beta whole square minus 2 alpha beta
therefore, 34=(8)^2- 2×alpha×beta
therefore, 34 = 64 - 2× alpha× beta
therefore, 2×alpha×beta= 64-34
therefore, 2×Alpha×Beta=30
therfore, alpha×beta=30/2 = 15
The required quadratic equation is x^2 - (alpha + beta)x + alpha×beta=0 answer is x^2 - 8 x + 15=0
^ this means raise to the power
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The required quadratic equation is x²-8x+15
• Given α+β = 8
and α²+β² = 34
• we know the formula of (α²+β²) = α²+β²+2αβ
• So, α²+β² can be written as
α²+β² = (α+β)²-2αβ
• So, (α+β)²-2αβ = 34 ...(1)
• We had the value of α+β = 8
•So,from (1)
(8)²-2αβ = 34
64-2αβ = 34
2αβ = 64-34 = 30
• Therefore, αβ = 15
• we know the quadratic equation having roots α and β is
x²-(α+β)x+αβ = 0 ...(2)
• We have got αβ = 15,(α+β) = 8
• Substituting the values in equation (2)
x²-(8)x+15 = 0
•Therefore,the quadratic equation is x²-8x+15 = 0.
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