If alpha + beta = . prove that: (1 + tan a) (1 + tan B) = 2
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we have,
A + B = π/4
Taking tan both sides
tan(A+B) = tanπ/4
tan A + tan B/ 1- tan A tanB = 1
tanA + tan B = 1- tanA tanB
tan A + tanB + tanAtanB = 1
Adding 1 both sides.
1 + tan A +tanB + tanA tanB = 2
1(1+tanA ) + tanB( 1+tan A) = 2
(1+tanA) ( 1+tan B ) = 2
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