if alpha, beta y the zeros of a cubic polynomial "x³+ 5x²+4" the value of alpha,beta y is
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0
Answer:
Step-by-step explanation:
If alpha, beta, gamma are zeros of cubic polynomial x^3 + 5x - 2, what is the value of alpha^3 + beta^3 + gamma^3?
x³ + 5x – 2
a=1, b=0, c=5, d= - 2
Comparing we get
α+ β+γ = -b/a=0
αβ + αγ+β γ=c/a=5
αβγ=-d/a = 2
Since α,β,γ are zeroes of given equation
Answered by
0
Answerx
3
++4x
2
−5x−2
The expression is in the form ax
3
+bx
2
+cx+d,then
a=1,b=4,c=−5,d=−2
∴α+β+γ=
a
−b
=
1
−4
=−4
αβ+βγ+γα=
a
c
=
1
−5
=−5
αβγ=
a
−d
=
1
−(−2)
=2
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