Question

If alpha,bit a are zeros of x^2-x-6 find alpha-bita

Answer 1

Answer:

(5 0r -5)

Step-by-step explanation:

x^2-x-6=0

6 can be written as products of(2*3) and (5*1)

Here we choose (2*3)

x^2-3x+2x-6=0  (grouping terms to obtain factors)

x(x-3) +2(x-3)=0       ;  (x-3)(x+2)=0 [now equate each term to zero ]

Therefore the two roots are 3,-2

M1-if (alpha=3 ,beta =-2)

then (alpha -beta =5)

M2 -if (alpha=-2 ,beta =3)

then (alpha -beta =-5)