if alpha+bita=90degre and sin alpha=1/3 then sin bita
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if sin alpha is 1/3 and alpha +bita= 90 degree then
alpha=(90-bita)
multiplying sin in both sides we get
sin(alpha)=cos(bita)
then cos bita=1/3
sin(bita)=√1-cos^2(bita)
so sin bita =2√2/3
alpha=(90-bita)
multiplying sin in both sides we get
sin(alpha)=cos(bita)
then cos bita=1/3
sin(bita)=√1-cos^2(bita)
so sin bita =2√2/3
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