Question

If alpha-bita, alpha and alpha +bita r zeroes of polynomial x cube-12xsquare+39x-28, then find alpha

Answer 1

here is your answer

hope this helps you

Answer 2

Answer :-

α = 4

Solution :-

Given :-

( α - β ) , α and ( α + β ) are the zeroes of x³ - 12x² + 39x - 28

x³ - 12x² + 39x - 28

Comparing with ax³+ bx² + cx + d we get,

• a = 1
• b = - 12
• c = 39
• d = - 28

Sum of zeroes = - b/a

⇒ ( α - β ) + α + ( α + β ) = - ( - 12 ) / 1

⇒ α - β + α + α + β = 12

⇒ 3α = 12

⇒ α = 12 / 3 = 4

Therefore the value of α is 4.