Question

If alpha,bita are the roots of 3x^2+3x+1=0,find the equation whose roots are 1-alpha/1+alpha,1-bita/1+bita

Who solved this problem I will mark as brainlist

Answer 1

Answer:

α+β= 2/3

And

α.β=−3

Therefore,

α^2 +β^2 =(α+β)^2 −2αβ

= 9/4 +6

= 33/4

Hence, the equation will be

x ^2 −( 33/4 +4)x+(9+2( 33/4 +4)=0

4x ^2 −49x+118=0.

Step-by-step explanation:

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