If alpha bita are the zeroes of the polynomial x²+7x+7 then find the value of 1/alpha+1/bita-2alphabita
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Hi there!
Here's your answer :-
Given --
α and β are zeroes of polynomial x² + 7 x + 7
→ Sum of zeroes, α + β = -b / a = -(7) / 1 = -7
→ Product of zeroes, αβ = c / a = 7 / 1 = 7
Now,
1/α + 1/β + 2 αβ
= (α + β) / αβ + 2 αβ
= -7 / 7 - 2 × (7)
= -1 - 14
= -15
Hence,
The required answer is :- [ - 15 ]
Hope it helps!
Here's your answer :-
Given --
α and β are zeroes of polynomial x² + 7 x + 7
→ Sum of zeroes, α + β = -b / a = -(7) / 1 = -7
→ Product of zeroes, αβ = c / a = 7 / 1 = 7
Now,
1/α + 1/β + 2 αβ
= (α + β) / αβ + 2 αβ
= -7 / 7 - 2 × (7)
= -1 - 14
= -15
Hence,
The required answer is :- [ - 15 ]
Hope it helps!
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