if alpha Bita are the zeros of the equation 6x square + x - 2, find a/b + B/a
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(alpha+beta)= -b/a
=-(-2/6)
=1/3
alpha beta. =c/a
=-2/6
=-1/3
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Answer:
Since a and B are roots of eqn :
So we know :
(a+b) = -1/6
ab = -1/3
(a+b)^2 = 1/36 = a^2 + b^2 + 2ab
So on inputting value of ab :
a^2 + b^2 -2/3 = 1/36
a^2 + b^2 = 25/36
Dividing the whole equation by:
(a^2 + b^2)/ab = 25/36.ab
a/b + b/a = 25/36(-1/3) = -25/12.
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