Math, asked by ak2476075, 11 months ago

if alpha. bitaa are the zero of the polynomial f (x) x2-3x+2 than find 1/alpha+1/ bitaa ​

Answers

Answered by TrickYwriTer
2

Step-by-step explanation:

Given -

  • α and β are zeroes of the polynomial f(x) = x² - 3x + 2

To Find -

  • Value of 1/α + 1/β

→ β + α/αβ

Method 1 :-

Now,

→ x² - 3x + 2

By middle term splitt :-

→ x² - x - 2x + 2

→ x(x - 1) - 2(x - 1)

→ (x - 2)(x - 1)

Zeroes are -

→ x - 2 = 0 and x - 1 = 0

→ x = 2 and x = 1

Then,

The value of 1/α + 1/β is

→ 1/1 + 1/2

→ 2 + 1/2

→ 3/2

Hence,

The value of 1/α + 1/β is 3/2

Method 2 :-

As we know that :-

  • α + β = -b/a

→ α + β = -(-3)/1

→ α + β = 3

And

  • αβ = c/a

→ αβ = 2/1

→ αβ = 2

Then,

The value of 1/α + 1/β or α + β/αβ is

→ 3/2

Answered by silentlover45
0

\large{\boxed{\underline{\underline{\bf{\red{Answer:-}}}}}}

\implies x = 2

\implies x = 1

\large\underline\mathrm{Given:-}

  • β and α x² - 3x + 2 are zeroes of the polynomial f(x) = x² - 3x + 2

\large\underline\mathrm{To \: find}

  • Value of 1/α + 1/β

\implies β + α/βα

\large\underline\mathrm{Now,}

\implies x² - 3x + 2

\implies x² - x - 2x + 2

\implies x(x - 1) - 2(x - 1)

\implies (x - 2)(x - 1)

\implies x - 2 = 0

\implies x = 2

\implies x - 1 = 0

\implies x = 1

\large\underline\mathrm{Then,}

\large\underline\mathrm{The \: value of \: 1/α \: + 1/β \: is \: 3/2 \: .}

\implies α + β = -b/a

\implies α + β = -(-3)/1

\implies α + β = 3

\large\underline\mathrm{And}

\implies βα = c/a

\implies βα = 2/1

\implies βα = 2

\large\underline\mathrm{Then,}

\large\underline\mathrm{The \: value of \: 1/α + \: 1/β \: or  \: α \: + \: β/βα \: is \: 3/2 \: .}

\large\underline\mathrm{Hope \: it \: helps \: you \: plz \: mark \: me \: brainlist}

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