if alpha, Britia and the zeros of the polynomial p (x) =ax2 +bx+c, then 1/alpha square +1 /bita squares
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Answer:
(b^2-2a)/c
Step-by-step explanation:
alpha+bita=-b/a,alpha*bita=c/a
to prove : 1/alpha^2+1/bita^2
=(bita^2+alpha^2)/(alpha*bita)^2
=[(alpha +bita)^2-2alpha*bita]/(alpha*bita)^2
=[(-b/a)^2-2c/a]/(c^2/a^2)
=[(b^2/a^2)-(2c/a)]*a^2/c^2
=(b^2-2a)/c
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