if alpha is equal to 30 degree and beta is equal to 60 degree then verify tan (alpha+beta) is equal to tan alpha+tan beta /1-tan alpha into tan beta .
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Step-by-step explanation:
If 0≤α,β≤90
o
and tan(α+β)=3 and tan(α−β)=2 then value of sin2α is?
If 0≤α,β≤90
o
and tan(α+β)=3 and tan(α−β)=2 then value of sin2α is?
Answered by
0
Answer:
it is proof that tan(α+β)=tanα+tanβ/1-tanαtanβ
and given that α=30&β=60
onputting on L.H.S=tan90 which is not defined
and in denominator of R.H.S Value is 1-tanαtanβ
tanα=tan30=1/√3
tanβ=tan60=√3
1/√3*√3 =1 and 1-1=0 so now 0 comes in denominator and value/0 is not defined hence L.H.S = R.H.S
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