English, asked by kekekeerthi053, 7 months ago

. If alphaand beta are the zeroep of the quadratic polynomial p(x)=5x^2-7x+1
find the value of 1/alpha+ 1/beta​

Answers

Answered by Anonymous
4

Answer:

7

Explanation:

Let's denote alpha by x and beta by y. And x and y are the zeros of the polynomial.

So, we have to find the value of 1/x + 1/y.

Given polynomial: 5x² - 7x + 1 where a is 5, b is -7 and c is 1.

Sum of zeros = -b/a

x + y = -(-7)/5

x + y = 7/5

Product of zeros = c/a

xy = 1/5

Now,

→ 1/x + 1/y = (x + y)/xy

Substitute the values,

→ (7/5)/(1/5)

→ 7

Hence, the value of 1/alpha + 1/beta is 7.

Answered by Anonymous
9

Answér :

7

Solution :

  • 1/alpha + 1/beta = -b/c
  • 1/alpha + 1/beta = -(-7)/1
  • 1/alpha + 1/beta = 7

Formula used :

  • 1/alpha + 1/beta = -b/c

For information related to the proof of the formula please refer to the following question añswered by me

https://brainly.in/question/21061855

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