if alphad beta are the zeros of 4x^2-5x-l. Find the values of alpha^4 × beta ^3 + alpha^3× beta ^4
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alpha is 1 and beta is 1/4
(1)^4 ×(1/4)^3+(1)^3×(1/4)
(1/64)+(1/256)
4+1/256
5/256
(1)^4 ×(1/4)^3+(1)^3×(1/4)
(1/64)+(1/256)
4+1/256
5/256
Trusha11:
Could you explain a little more briefly?
its ok
or briefly
I need a little more detailed explanation
how is alpha one and beta 1/4?
by middle term splitting
Oh alright! Thanks!
hmm
Answered by
0
Mark me brainiest please
I never got one
I never got one
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This actually has an error
You are not supposed to add the powers. Only the bases should be added since the powers are same
So, the solution turns out to be like this; (alpha × beta)^3 × alpha +beta. By substituting the values we get 5/256.
thank you so much Trusha11 for correcting it
Anytime!
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