Question

If alphs and ß are the zeroes
polynomial p(x)= x² - 2x + 8.
value of alpha3 beta2 + alpha2 beta3
of the
Find the​

Answer 1

Answer:

128

Step-by-step explanation:

$p(x)=x^2-2x+8$

Finding the zeroes isn't needed.

SUM $\alpha +\beta =2$

MULTIPLICATION $\alpha \beta =8$

Thus $\alpha^2 \beta^2 (\alpha +\beta )=64\times2=128$.

Answer 2

Step-by-step explanation:

p(x) = x^2 - 2x - 8

. let p(x) = 0

. then x^2 -4x + 2x -8 = 0

. → x ( x - 4) + 2(x-4) = 0

. → ( x-4) (x+2). = 0

. →. x= 4 and -2

Now alpha = 4 and beta = -2

then putting the values according to question, we get

alpha ^3 beta ^ 2+ alpha ^2+beta^ 3

.

=. 4^3 (-2)^2 t 4^2+ (-2)^ 3

=. 256 - 128

=. 128