If alspha and beta are the zeroes of tge polynomial 4x^2+2x+(k-4) and alpha. = 1÷beta find the valur of k
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Heya !!!
P(X) = 4X²+2X+(K-4)
Here,
A = 4 , B = 2 and C = ( K-4)
Product of zeroes = C/A
Alpha × Beta = (K-4)/4
1/Beta × Beta = (K-4)/4
1 = K -4/4
K -4 = 4
K = 4+4
K = 8.
HOPE IT WILL HELP YOU....... :-)
P(X) = 4X²+2X+(K-4)
Here,
A = 4 , B = 2 and C = ( K-4)
Product of zeroes = C/A
Alpha × Beta = (K-4)/4
1/Beta × Beta = (K-4)/4
1 = K -4/4
K -4 = 4
K = 4+4
K = 8.
HOPE IT WILL HELP YOU....... :-)
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