If AM and CN are perpendiculars on the diagonal BD of a parallelogram ABCD, Is ∆AMD = ∆CNB? Give reasons.
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Answer:
in triangle AMB and triangle DNC
AB=DC(opp. sides of parallelogram is equal)
angle AMB =angle DNC (both 90)
angle abm =angle cdb (alternate angles)
so, AMB congurent DBC by(AAS)
AM=CN by(cpct)
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