if AM and CN are perpendiculars on the diagonal BD of a parallelogram ABCD, Is ∆AMD = ∆CNB? Give reason. (NCERT Exemplar)
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Step-by-step explanation:
AM and CN are perpendicular to the diagonal BD of a parallelogram ABCD
In a Parallelogram ABCD
AB = CD
BC = AD
BD is diagonal
ΔABD & ΔCDB
AB = CD
AD = CB
BD = BD ( common)
ΔABD ≅ ΔCDB
Area of ΔABD = Area of ΔCDB
AM and CN are perpendicular to the diagonal BD
=> Area of ΔABD = (1/2) BD * AM
Area of ΔCDB = (1/2) BD * CN
(1/2) BD * AM = (1/2) BD * CN
=> AM = CN
QED
Proved
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