Question

If Am and cofficeint of variation of x are 10 and 50 respectively, what is the variants of (15-2x)
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Answer 1

Answer:

answer is 60 of variants of 25- 2 x

Answer 2

Answer:

C.V. = Standard Deviation /Mean. So, st. dev. = CV x Mean = 50 x 10 = 500. Or Var (x) = 250000 Now, Var (15-2x) = 4 Var (x) = 640000

[use var(y) = E {y- Mean (y)}^2 = E {(15-2x)-Mean (15–2x)}^2 = 4E {x-Mean (x)}^2 = 4 x var (x)}