If Am and cv of a random variables x are 10 & 40 then variance of (_-15+3x/2)?
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Step-by-step explanation:
C.V. = Standard Deviation /Mean. So, st. dev. = CV x Mean = 40 x 10 = 400. Or Var (x) = 160000 Now, Var (15-2x) = 4 Var (x) = 640000
[use var(y) = E {y- Mean (y)}^2 = E {(15-2x)-Mean (15–2x)}^2 = 4E {x-Mean (x)}^2 = 4 x var (x)}
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