If 'am' is not equal to 'bl', then the system of equations 'ax +by=c' and 'lx+my=n'
(a) has unique solution
(b) has no solution
(c) has infinitely many solutions
(d) may or may not have solution
please give me solution earliest as possible
Answers
CORRECT ANSWER IS OPTION A
HOPE THIS HELPS YOU
Step-by-step explanation:
If am ≠ bl, then the equations ax+by=c, lx+my=n has a unique solution.
Given,
Pair of lines represented by the equations
ax + by = c
lx + my = n
For unique solution
\frac{a}{l} \neq \: \frac{b}{m}
l
a
=
m
b
For infinite solutions
\frac{a}{l } = \frac{b}{m} = \frac{c}{n}
l
a
=
m
b
=
n
c
For no solution
\frac{a}{l } = \frac{b}{m} \neq \frac{c}{n}
l
a
=
m
b
=
n
c
Given,
a \times m \neq \: b \times la×m
=b×l
This can be transformed into
\frac{a}{l} \neq \: \frac{b}{m}
l
a
=
m
b
Therefore, If am ≠ bl, then the equations ax+by=c, lx+my=n has a unique solution
Answer:
Answer:
ax+ by = c
lx + my = n
a1 = a. , a2= l
b1 = b. , b2= m
c1 = c. ,c2= n
it is given that,
am ≠ bl
therefore, a/l ≠ b/m
so, it has a unique solution
so, option a is a correct answer