Question

if amount (a) = rd 2500 and principal ( p) =2000 fine the instereat of it​

Answer 1

Answer:

Given:−

Principal = ₹2500

Time = 3 years

Rate = 6%

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ToFind:−

Simple Interest

Amount

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Answer:−

Principal (P) = ₹2500 , Time = 3years and Rate = 6%

➡ Simple Interest (I) = \frac{P×T×R}{100}

100

P×T×R

= \frac{2500\times 3\times 6}{100}

100

2500×3×6

= ₹450

➡ Amount = Simple Interest + Principal

= ₹2500+₹450

= ₹2950

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RequiredAnswer:−

Simple Interest = ₹450

Amount = ₹2950

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Formulas used here:-

Simple Interest = \frac{Principal×Time×Rate}{100}

100

Principal×Time×Rate

I = \frac{P×T×R}{100}

100

P×T×R

Amount = Principal + Simple Interest

A = P + I

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Additional Information:-

If Simple Interest (I) , Time ( T) and Rate (R) are given, the formula used for finding Principal(P) :-

P = \frac{I×100}{R×T}

R×T

I×100

If Simple Interest (I) , Principal (P) and Rate (R) are given, the formula used for finding Time(T) :-

T = \frac{I×100}{P×R}

P×R

I×100

If Simple Interest (I) , Principal (P) and Time (T) are given, the formula used for finding Rate ( R) :-

R = \frac{I×100}{P×T}

P×T

I×100

Answer 2

Answer:

Amount = principle + simple interest

simple interest = amount - principle

= 2500 - 2000

SI = 500