Question

If amount of current flowing in appliance is doubled then energy consumed by it is doubled (by P=VI) or quadrupled (four times by H=I²Rt)? Which concept has to be applied?​

Answer 1

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betweem 52 kg and 53kg

Step-by-step explanation:

mean of weight of 5 students = 51kg

the total weights of the five students= 51 x 5 = 255

mean weight of 4 students =54

the total weight of four students = 54 x 4 = 216

add the total weights of 5 and 4 students

255 + 216 = 471

471 diveded by nine

471/9 = 52.33

the answer is 52.33 so ut us between 52 and 53

Explanation:

Answer 2

Answer:

Energy (power×time) is measured in Joules and by including time (t) in the power formulae, the energy dissipated by a component or circuit can be calculated.

Energy dissipated = Pt or VI×tasP=VI.

It can also be written as I

2

×RtasV=IR.

Hence, the expression for Power in terms of current is given as P=I

2

RtJ.

Therefore, if I becomes 2I, then P

′

=(2I)

2

R×t=4(I

2

R×t).

Hence, if the current passing through an electric bell is doubled, the heat produced will become four times more.