Math, asked by Anonymous, 24 days ago

If & and B are the zeroes of the quad polynomial f(x) = x² - p(x +1)-&, show that (a +1) ( beta + 1 ) = 1-

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Answered by itztalentedprincess
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Answered by amritariyazshraddha
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Sᴏʟᴜᴛɪᴏɴ:-

If alpha and Beta are the zeroes of the polynomial x^2-p(x+1)-c, find the value of (alpha +1)(beta+1)

Asked by Nimmi | 7th May, 2019, 11:36: PM

Expert Answer:

If alpha and Beta are the zeroes of the polynomial x^2-p(x+1)-c, find the value of (alpha +1)(beta+1)

x2 - p(x + 1) - c

= x2 - px - p - c

Comparing with ax2 + bx + c, we get

a= 1 , b = -p and c = - p - c

α and β are the zeroes of the given polynomial.

→ α + β = -b/a = -(-p)/1 = p

and αβ = c/a = -p - c / 1 = -p - c

To find: (α + 1)(β + 1)

(α + 1)(β + 1) = αβ + α + β + 1

= - p - c + p + 1

= 1 - c

Step-by-step explanation:

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