Question

If α & β are the zeroes of polynomial : 2x² - 7x +3 . Find the value of ( i ) 1/α + 1/ β.

Answer 1

Answer:

7/3

Step-by-step explanation:

→ 2x² - 7x + 3 → 2{x² - (7/2)x + (3/2)}

Polynomials written in form of k(x² - Sx + P), represent S as sum of their roots and P as product of roots.

So, here, if α and β are roots:

• α + β = 7/2

• α*β = 3/2

So,

= > 1/α + 1/β

= > (α + β)/α*β

= > (7/2)/(3/2)

= > 7/3

Answer 2

Answer:

⭐ Given ⭐

✍ If α & β are the zeroes of polynomial : 2x² - 7x +3 .

⭐ To find ⭐

✍ 1/α + 1/ β.

⭐ Solution ⭐

=> 2x²-7x+3

=> 2{x²-(7/2)x + (3/2)}

➡ Polynomial can be written as

✍ k(x² - SX + P)

Where,

⚫ S = Sum of the roots.

⚫ P = Product of the roots.

⭕ So here, α and β are the roots,

✏ α + β = 7/2

✏ α × β = 3/2

➡ Now,

=> 1/α = 1/β

=> (α + β) / α × β

=> (7/2)/(3/2)

=> 7/3✔

✍ The value of 1/α+1/ β = 7/3.

Step-by-step explanation:

HOPE IT HELP YOU