If α&β are zeroes of a quadratic polynomial x-px+q=0 then find 1/α+1/β
Answers
Answered by
5
1/α + 1/β
= (α+β)/αβ
For an equation ax²+bx+c=0
α+β= -b/a
αβ= c/a
Given equation is x²-px+q
a=1 b=-p c=q
Substituting values
(p/1)/(q/1)
=p/q
= (α+β)/αβ
For an equation ax²+bx+c=0
α+β= -b/a
αβ= c/a
Given equation is x²-px+q
a=1 b=-p c=q
Substituting values
(p/1)/(q/1)
=p/q
Answered by
3
Heya !!!
here is your answer!!!
x² - px + q = 0
sum of zeros = p
Product of zeroes = q
now ,
=> 1 / alpha + 1 / ß
=> alpha + beta / alpha *ß
=> p /q
hence ,
=> p / q
hope it helps you dear !!!
thanks !!!
here is your answer!!!
x² - px + q = 0
sum of zeros = p
Product of zeroes = q
now ,
=> 1 / alpha + 1 / ß
=> alpha + beta / alpha *ß
=> p /q
hence ,
=> p / q
hope it helps you dear !!!
thanks !!!
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