Math, asked by jishanmansoori4785, 1 year ago

If α&β are zeroes of a quadratic polynomial x-px+q=0 then find 1/α+1/β

Answers

Answered by UnknownDude
5
1/α + 1/β
= (α+β)/αβ
For an equation ax²+bx+c=0
α+β= -b/a
αβ= c/a
Given equation is x²-px+q
a=1 b=-p c=q
Substituting values
(p/1)/(q/1)
=p/q
Answered by RanjanKumar14
3
Heya !!!


here is your answer!!!


x² - px + q = 0




 \alpha  \: and \:  \beta  \: are \:  \: the \: zeroes


sum of zeros = p



Product of zeroes = q


now ,


=> 1 / alpha + 1 / ß

=> alpha + beta / alpha *ß



=> p /q


hence ,



1 \div  \alpha  + 1 \div  \beta
=> p / q



hope it helps you dear !!!

thanks !!!
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