If amphotin mon of AP is 1 by an and answer term is 1 by and then find the sum of its first mn terms
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10th
Maths
Arithmetic Progressions
Sum of an AP
If mth term of an AP is 1/n...
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If mth term of an AP is 1/n and nth term is 1/m then find the sum of its first mn terms.
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ANSWER
Let a be first term and d be the common difference of an AP.
mth term=1/n
so,
a
m
=a+(m−1)d=1/n .........(1)
nth term=1/m
a
n
=a+(n−1)d=1/m ........(2)
Subtract (2) from (1)
(m−1)d−(n−1)d=
n
1
−
m
1
d(n−n)=
mn
m−n
d=1/mn .........(3)
From (3) and (1), we get
a+(m−1)×
mn
1
=
n
1
⇒a=
n
1
−
mn
m−1
a=
mn
1
Sum of first k terms =(k/2)[2a+(k−1)d]
S
mn
=mn/2[2(1/mn)+(mn−1)(1/mn)]
=mn/2[1/mn+1]
=(1+mn)/2.
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