if an=2n+3 nind S1,S2,S3.
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Step-by-step explanation:
T
n
=2n+3 then,
T
1
=(2×1)+3=2+3=5
T
2
=(2×2)+3=4+3=7
T
3
=(2×3)+3=6+3=9
Therefore, S
3
is the sum of T
1
, T
2
and T
3
that is:
S
3
=T
1
+T
2
+T
3
=5+7+9=21
Hence, S
3
=21.
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