If an = 3+4n, find the sum of first 11 terms.
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Step-by-step explanation:
Tn= 3+4n
T1 = first term (a) = 3+(4×1)=7
T2 = 2nd term = a+d= 3+(4×2)=11
d = 11-7 =4
Sum of 11 terms= 11/2[2×7+(11-1)4)]=297
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