Math, asked by Yadvindersingh3778, 6 months ago

If an = 3+4n, find the sum of first 11 terms.

Answers

Answered by nirupamkrchy
0

Answer:

and this is a answer

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Answered by abhisheksolanki62
0

Step-by-step explanation:

Tn= 3+4n

T1 = first term (a) = 3+(4×1)=7

T2 = 2nd term = a+d= 3+(4×2)=11

d = 11-7 =4

Sum of 11 terms= 11/2[2×7+(11-1)4)]=297

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