if an =3+4n then find first term ,second term common difference and 20th term
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If an = 3 + 4n
Then, putting the value of n = 1, 2 , 3 we get,
a1 = 3 + 4 × 1 = 3 + 4 = 7
a2 = 3 + 4 × 2 = 3 + 8 = 11
a3 = 3 + 4 × 3 = 3 + 12 = 15
Now , we get
first term( a1) = 7
second term (a2) = 11
so,.
common difference(d) = ( 2nd term - 1st term)
d = ( a2 - a1 )
d = ( 11 - 7 )
d = 4
.now ,
a20 = a + ( n - 1) d
a20 = 7 + ( 20 - 1 ) 4
a20 = 7 + 19 × 4
a20 = 7 + 76
a20 = 83
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