If an A. P. consists of n terms with first term a and nth term l show that the sum of the nthterm from the beginning and the mth term from the end is (a + l).
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Step-by-step explanation:
mth term from the beginning is t(m)
mth term from the end is t( n−m+1 ) th term from the beginning
t(m) + t(n-m+1)
= a+(m-1)d + a + (n-m)d
=a + md-d + a + nd-md
=a +{a+ nd-d}
=a + {a+(n-1)d}
=a + l
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