If an A.P. has only n terms, its nth term (last term) is denoted by letter
Thus for an A.P. with first term = a. common difference = d and nu
terms = n, we have 1 = a + (n - 1)d.
For an A.P., t = a + (n - 1)d
if d > 0, the A.P. is increasing,
if d < 0, the A.P. is decreasing and
if d = 0, all the terms of the A.P. are same.
3
Find the A.P. whose nth term is 2n - 3.
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Answer:
I think the question lies only in the last line, so the answer goes like this :-
n th term = 2n-3 => ist term = 2×1-3 = -1
2 nd term = 2×2-3 = 1
3 rd term = 2×3-3 = 3
4th term = 2×4-3 = 5
thus, required A.P. = -1, 1, 3, and 5.
hope it helps
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