If an A.P. is 10, 7, 4, ....., -62, find the 11th
term from its end.
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answer for the given problem is given
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fact:- when we find common difference from the end the sign will be change
common difference =7-10 = -3 sign will be change
D = 3
AP from end the first term will be - 62
a11 = a1+10d
= -62+30= -32
hence AP from the end of 11th term will be -32
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