Question

If an alloy requires copper, nickel, and zinc in a ratio of 12:5:3, how many kilograms of each metal are needed to make 5 kg of the alloy?

Answer 1

Answer:

copper=12*1/4=3=3kg

nickel=5*1/4=1.25kg

zinc=3*1/4=.75kg

Step-by-step explanation:

Answer 2

3 kg of copper, 1.25 kg of nickel and 0.75 kg of zinc are needed to make 5 kg of the alloy.

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Let's solve the given problem:

The ratio of copper, nickel and zinc required in the alloy = 12 : 5 : 3

So, we can say,

"12x" → represents the weight of copper

"5x" → represents the weight of nickel

"3x" → represents the weight of zinc

The weight of the alloy = 5 kg

Therefore, we can form an equation as,

$12x + 5x + 3x = 5$

$\implies 20x = 5$

$\implies x = \frac{5}{20}$

$\implies x = \frac{1}{4}$

Now, by substituting the value of $x = \frac{1}{4}$, we get

Weight of copper = $12x = 12 \times \frac{1}{4} = \bold{3\:kg}$

Weight of nickel = $5x = 5\times \frac{1}{4} = \bold{1.25\:kg}$

Weight of zinc = $3x = 3\times \frac{1}{4} = \bold{0.75\:kg}$

Thus, 3 kg of copper, 1.25 kg of nickel and 0.75 kg of zinc are needed to make 5 kg of the alloy.

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