if an Angle differs from its complementary by 10°,find the angle
Answers
Answered by
5
let the one angle be x
other angle = 90 - x
x-(90-x) = 10
x-90+x = 10
2x = 10+90
2x = 100
x = 50°
Other angle = 90-x
= 90-50
= 40°
Hope it helps u : )
other angle = 90 - x
x-(90-x) = 10
x-90+x = 10
2x = 10+90
2x = 100
x = 50°
Other angle = 90-x
= 90-50
= 40°
Hope it helps u : )
tejasri2:
brainliest plz.
Answered by
4
Hey!!!...Here is ur answer
Since the angles are complimentary then..
If one angle is x then other will be x+10
So.. x+x+10=90
2x=80
x=40
So the angles are 40° and 50°
Hope it will help you
Since the angles are complimentary then..
If one angle is x then other will be x+10
So.. x+x+10=90
2x=80
x=40
So the angles are 40° and 50°
Hope it will help you
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