If an angle exceeds 3 times its complement by 10 degrees then find that angle
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Let,
the angle = x
according to the question,
(180-x) = 3(90-x)
180 - x = 270 -3x
-x+3x = 270-180
2x = 90
x = 45
the angle = x
according to the question,
(180-x) = 3(90-x)
180 - x = 270 -3x
-x+3x = 270-180
2x = 90
x = 45
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