If an angle exceeds complement by 20 degree find angle and complement
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Answered by
14
let the angle be x
then, it's compliment = x+20
ATQ
x+(x+20)=90°
x+x+20=90°
2x=90-20
2x=70
x=70÷2
x=35°
hence the two angles are 35°and 55°.
Hope this helps!!
then, it's compliment = x+20
ATQ
x+(x+20)=90°
x+x+20=90°
2x=90-20
2x=70
x=70÷2
x=35°
hence the two angles are 35°and 55°.
Hope this helps!!
Answered by
6
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