If an angle exceeds it's complement by 20degree find angle
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4
Let the angle be x°.
Therefore, the complement of the angle is (x+20)°.
According to the condition given,
x+(x+20)=90° {complementary angles sum up to 90°.}
x+x+20=90°
2x=90-20
2x=70
x=70/2
x=35°.
Therefore, the angle measures 35°.
Therefore, its complement, x+20
=35+20
=55°.
35+55=90.
PLS MARK AS BRAINLIEST.
Therefore, the complement of the angle is (x+20)°.
According to the condition given,
x+(x+20)=90° {complementary angles sum up to 90°.}
x+x+20=90°
2x=90-20
2x=70
x=70/2
x=35°.
Therefore, the angle measures 35°.
Therefore, its complement, x+20
=35+20
=55°.
35+55=90.
PLS MARK AS BRAINLIEST.
Answered by
1
let the angle be x .
then , another angle =y
it is given that x-y=20
therefore , x=20+y
now , adding x and y the result is complement I.e.90
therefore x+y=90
or y+20+y=90
or 2y=90-20
or y=35
therefore x =20+y
or x=20+35=55
then , another angle =y
it is given that x-y=20
therefore , x=20+y
now , adding x and y the result is complement I.e.90
therefore x+y=90
or y+20+y=90
or 2y=90-20
or y=35
therefore x =20+y
or x=20+35=55
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