If an angle is 10 degree more than its complement,find the angles
Answers
Answered by
53
Hey
Here is your answer,
Complimentary angles have a sum of 90.
m∠A+m∠B=90
m∠A=x
m∠B=x+10
10 more than the measure of its complement
x+x+10=90
2x+10=90
2x+10−10=90−10
2x=80
2x/2=80/2
x=40
x+10=50
Hope it helps you!
Here is your answer,
Complimentary angles have a sum of 90.
m∠A+m∠B=90
m∠A=x
m∠B=x+10
10 more than the measure of its complement
x+x+10=90
2x+10=90
2x+10−10=90−10
2x=80
2x/2=80/2
x=40
x+10=50
Hope it helps you!
Answered by
36
The complementary angles are 40° and 50°.
Step-by-step explanation:
Let the complement angle = x and (x + 10)
To find, the angles = ?
We know that,
The sum of the complementry angles = 90°
⇒ x + x + 10 = 90°
⇒ 2x = 90° - 10°
⇒ 2x = 80°
⇒ x = 40°
∴ x + 10° = 40° + 10° = 50°
Hence, the complementary angles are 40° and 50°.
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