If an angle is 10 more than its complement, find the angle
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18
Let the angles be x and x+10.
Sum of complementary angle = 90°
x + x + 10 = 90
2x = 90 - 10
2x = 80
x = 80/2
x =40°
So the angles are
X = 40° & x+10 = 50°
Hope it helps.
stargirl11:
hi
Answered by
3
Let the angles be x and x+10.
Sum of complementary angles = 90°
x + (x+10) = 90°
2x + 10 = 90°
2x = 90 - 10
2x = 80°
x = 80/2 = 40°
x= 40°
x+10 = 40 +10 = 50°
Therefore, the angles are 40° and 50°
Hope it would be helpful
PLS mark it as brainliest
Sum of complementary angles = 90°
x + (x+10) = 90°
2x + 10 = 90°
2x = 90 - 10
2x = 80°
x = 80/2 = 40°
x= 40°
x+10 = 40 +10 = 50°
Therefore, the angles are 40° and 50°
Hope it would be helpful
PLS mark it as brainliest
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