If an angle is 10º more than its complement, then find the angle?
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Answered by
1
Answer:
let first angle be x
2nd be x+10°
x+x+10°=90°
2x=90°-10°
x=80°/2
x=40°
this is your answer
Answered by
0
Answer:
let the angle be x then the other angle is x+10
sum of the 2 complement angle sis always 360° so x + x + 10 = 360
2x = 360-10
2x = 350
x = 350/2
x = 175°
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