if an angle is 30 more than half of its complement find the angles
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Hi ,
Let one angle = x ,
second angle = ( 90 - x )
according to the problem given ,
x - ( 90 - x )/2 = 30
=> [ 2x - ( 90 - x ) ] = 60
=> 2x - 90 + x = 60
=> 3x = 60 + 90
=> 3x = 150
x = 150/3
x = 50
Therefore ,
first angle = x = 50°
It's complement = 90 - x
= 90 - 50
= 40°
I hope this helps you.
: )
Let one angle = x ,
second angle = ( 90 - x )
according to the problem given ,
x - ( 90 - x )/2 = 30
=> [ 2x - ( 90 - x ) ] = 60
=> 2x - 90 + x = 60
=> 3x = 60 + 90
=> 3x = 150
x = 150/3
x = 50
Therefore ,
first angle = x = 50°
It's complement = 90 - x
= 90 - 50
= 40°
I hope this helps you.
: )
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