if an angle is 30° more than one half of its complement. find the angle
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let's take two angles =x and y
if x=30+y then,
x+y=90
30 +y+y=90
2y+30=90
2y=90-30
2y=60y
y=30
x=30+y
x=30 +30.... y=30
x= 60
so, x and y are 60 and 30 respectively
if x=30+y then,
x+y=90
30 +y+y=90
2y+30=90
2y=90-30
2y=60y
y=30
x=30+y
x=30 +30.... y=30
x= 60
so, x and y are 60 and 30 respectively
pranjjalika:
the answer is wrong
why
the answer is x=50°
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