Question

if an angle of a parallelogram is four fifths of its adjacent angle find the angle of the parallelogram

Answer 1

$<b>$As we know that Sum of adjacent angles of a parallelogram is 180°

Let the adjacent angle be x°

Hence, the angle required is (4x/5)°

A/Q

x + (4x/5)° = 180°

(5x + 4x/5)° = 180°

(9x/5)°= 180°

9x° = 180° × 5

x = (900/9)°

x = 100°

So,the adjacent angle = x = 100°

and the required angle = (4x/5)° = {(4 × 100)/5°

(400/5)° = 80°

Thanks

Have a colossal day ahead

Be Brainly

Answer 2

$\tt \large AHOY!! \:$

$\sf ATQ, an \: angle \: of \: a \: parallelogram \: is \: four \\ \sf fifths \: of \: its \: adjacent \: angle. \\ \\ \sf let \: its \: adjacent \: angle \: be \: x \\ \\ \sf \therefore \: the \: angle \: is \: \frac{4x}{5} \\ \\ \sf we \: know \: that \: the \: sum \: of \: two \: adjacent \\ \sf in \: a \: parallelogram \: is \: 180 \degree. \\ \\ > > \sf x + \frac{4 x}{5} = 180 \degree \\ \\ \sf > > \frac{x \times 5}{1 \times 5} + \frac{4x}{5} = 180° \\ \\ \sf > > \frac{9x}{5} = 180° \\ \\ \sf > > 9x = 180 \times 5 \\ \\ \sf > > 9x = 900 \\ \\ \sf >> x = \frac{900}{9} \\ \\ \sf >> x = 100°$

hence, the adjacy angles of the parallelogram are :-

• x = 100°

• 4x/5 = (4 × 100)/5

= 400/5

= 80°

other two adjacent angles are also 100° and 80° respectively as we know opposite angles of a parallelogram are equal.

$\tt \large HOPE \: IT \: HELPS!!$