Math, asked by sanskruti15, 1 year ago

if an angle of a parallelogram is two third of its adjacent angle then find the smallest angle of parallelogram


biluminous: I am not sure if my solution is wright or wrong.

Answers

Answered by Abhijeetpalkar
1
2/3x is smallest angle
Answered by biluminous
9
in a parallelogram
x + (2 \div 3)x = 180
(5 \div 3) \times x = 180
so,
x = 108 \: deg
and
(2 \div 3)x = (2 \div 3) \times 108
(2 \div 3)x = 72 \: deg
thus smallest angle is 72°.
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