if an angle of a parallelogram is two -third of its adjacent angle ,find the angle of the parallelogram??
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let one angle =x
adjacent angle =2x/3
in a parallelogram sum of adjacent angles are supplementary(180degree)
x+2x/3=180
(3x+2x)/3=180
5x/3=180
x =180*3/5
x=36*3
x =108
therefore
the angles in a parallelogram are
108,72,108,72
adjacent angle =2x/3
in a parallelogram sum of adjacent angles are supplementary(180degree)
x+2x/3=180
(3x+2x)/3=180
5x/3=180
x =180*3/5
x=36*3
x =108
therefore
the angles in a parallelogram are
108,72,108,72
Answered by
0
Answer:
let one angle =x
adjacent angle =2x/3
in a parallelogram sum of adjacent angles are supplementary(180degree)
x+2x/3=180
(3x+2x)/3=180
5x/3=180
x =180*3/5
x=36*3
x =108
therefore
the angles in a parallelogram are
108,72,108,72
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