if an angle of a parallelogram is two-third of the adjacent angle the smallest angle of a parallelogram
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let the adjacent angles be x
then , other angle = (2/3)x
we know opposite angles of parallelogram are equal .
=> and sum of all angles of a quadrilateral is 360°
therefore ,
we get ,
=> x+x+2x/3+2x/3 = 360°
=> 2x+4x/3 = 360°
=> (6x+4x)/3 = 360° (making denominator equal)
=> 10x/3 = 360°
=> x = 360×3/10
=> x = 36×3 = 108°
therefore , other angle = (2/3)x
=> (2/3)×108°
=> 2×36 => 72°
therefore , smallest angle of Parallelogram is 72°
hope this helps
please mark my answer as brainalist
then , other angle = (2/3)x
we know opposite angles of parallelogram are equal .
=> and sum of all angles of a quadrilateral is 360°
therefore ,
we get ,
=> x+x+2x/3+2x/3 = 360°
=> 2x+4x/3 = 360°
=> (6x+4x)/3 = 360° (making denominator equal)
=> 10x/3 = 360°
=> x = 360×3/10
=> x = 36×3 = 108°
therefore , other angle = (2/3)x
=> (2/3)×108°
=> 2×36 => 72°
therefore , smallest angle of Parallelogram is 72°
hope this helps
please mark my answer as brainalist
shree171:
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