If an angle of a rhombus is 50°, find the size of the angles of one of the triangles which are formed by the diagonals.
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Please solve this question it's urgent.
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Answered by
21
A rhombus has two opposite angle I.e A = C = 50°
so total angle of triangle = 180°
so
180° - (50° + 50°)
180° - 100°
And - 80°
so total angle of triangle = 180°
so
180° - (50° + 50°)
180° - 100°
And - 80°
Answered by
12
Since, in the tri.ABC, angle CAB = angle BCA = 50°.
From the angle sum property of a triangle, the sum of all angles of a triangle is 180°.
i.e., angle BAC+ angle BCA +angle ABC=180°.
50°+50°+ angle ABC=180°.
Therefore, the angle ABC =80°.
From the angle sum property of a triangle, the sum of all angles of a triangle is 180°.
i.e., angle BAC+ angle BCA +angle ABC=180°.
50°+50°+ angle ABC=180°.
Therefore, the angle ABC =80°.
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