Math, asked by abhishekchaurasiya82, 1 year ago

If an angle of a rhombus is 50°, find the size of the angles of one of the triangles which are formed by the diagonals.

Please solve this question it's urgent.

Attachments:

abhishekchaurasiya82: Please solve this question it's urgent.

Answers

Answered by SUMITMARANDI
21
A rhombus has two opposite angle I.e A = C = 50°

so total angle of triangle = 180°

so

180° - (50° + 50°)
180° - 100°

And - 80°

abhishekchaurasiya82: wrong
abhishekchaurasiya82: answer of this question is 25°, 65° and 90°
Answered by anchal024
12
Since, in the tri.ABC, angle CAB = angle BCA = 50°.

From the angle sum property of a triangle, the sum of all angles of a triangle is 180°.

i.e., angle BAC+ angle BCA +angle ABC=180°.
50°+50°+ angle ABC=180°.
Therefore, the angle ABC =80°.

abhishekchaurasiya82: wrong
anchal024: how?
abhishekchaurasiya82: answer of this question is 25°, 65° and 90°
anchal024: how?
SUMITMARANDI: if you know the answer then why are you asking here
anchal024: If you are conflicting, so it is necessary to know. Right?
abhishekchaurasiya82: explain
anchal024: by the angle sum property of a triangle.
Similar questions