if an angles of a parallelogram is two-thirds of the adjacent angle.find the angle of the parallelogram ?
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let the angle be a b c and d
where a is equal to C and b is equal to d
2/3a=b
we know that the sum of angle of Telegram is 360 degree
2(2/3a)+2(a)=360
(4a+6a)/3=360
10a= 360×3
a= 108
b= 108×2/3
b=72
where a is equal to C and b is equal to d
2/3a=b
we know that the sum of angle of Telegram is 360 degree
2(2/3a)+2(a)=360
(4a+6a)/3=360
10a= 360×3
a= 108
b= 108×2/3
b=72
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